Empirical Formula

Today in class we went over some of the notes and discussed the empirical formula.
Sample Problem: 71.65% Cl, 24.27% C, 4.07% H
1. assume 100 grams
a. 71.65 g.*(1 mol./35.5 g.)
b. 24.27 g.*(1 mol./12 g.)
c. 4.07 g. *(1 mol./1g.)

2. convert grams to moles
a. 2.02 mol.
b. 2.02 mol.
c. 4.07 mol.

3. calculate ratio
a. 2.02/2.02=1
b. 2.02/2.02=1
c. 4.07/2.02=2.01=about 2

4. empirical formula is CClH2

5. relate empirical formula to molecular formula (molar mass)
(49.5 g.)*2=
98.96 g/mol.

The next scribe will be Bailey Monte