Tuesday, November 30, 2010

Percent Yield


The theoretical yield is the amount of product that can be made in a complete reaction. The actual yield is the amount of product that is actually obtained in an experimental setting. For many reasons your actual yield will be lower than the theoretical yield, that is why we do a percent composition.
Here is a percent yield problem we did during class.
C12H22O11 -----> 11H2O + 12C

eq=70.0gC12H22O11x\frac{1\phi C12H22O11}{342g}x\frac{12\phi C}{1\phi C12H22O11}x\frac{12gC}{1\phi C}= 29.5g C

In class we ran this experiment and got a mass of 241.84 grams. From this value you must subtract the mass of the beaker, 155.20 grams, and the mass of the sulfuric acid, 59.06 grams. This leaves you with the mass of the carbon which is 27.58 grams.

Now to get the precent yield you use the formula at the top of the post.
eq=(\frac{27.58 g}{29.5 g})x100=93.5
Your final precent yield is 93.5%. I hope this will help you understand percent yields.
The next scribe will be... Chris A.

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