Today we started off class by going over question #3 on the SuperMole Fun worksheet. The point of this problem is to find the amount of bacteria tissue (C5H7O2N) produced. In the problem you are given the kg of waste to start (10000 kg). You need to convert this into NH4+ ions so you multiply by 3.o kg NH4+ / 100 kg waste. Since the problem says the waste water contains 3% NH4+ ions, we can assume 100 kg. After converting to NH4+, multiply by 1000g / 1 kg so the equation is converted to grams. Next, you find the molar mass of NH4+, which is 18.04. Multiply the equation by 1 mol NH4+ / 18.04 g NH4+ to convert it into moles. After this you use the conversion factor 1 mol C5H7O2N / 55 mol NH4+ to convert the equation into moles of C5H7O2N. Next, you find the molar mass of the bacterial tissue which is 113 g and use the conversion factor of 113 g / 1 mol C5H7O2N to convert the equation into grams. The grams of bacterial tissue produced should be 34000 g. Once you have found this, multiply it by 0.95 (95%) because in the problem it says that only 95% of ammonium (NH4+) ions are consumed by the bacteria. If you had some trouble following this, the answers and work are posted here. After going over the worksheet, we started our Copper and Silver Nitrate Lab by going over the pre lab and procedures. This lab is going to take multiple days, so we haven't finished it yet, but it is due on tuesday of next week. Also, our class could probably make a huge profit by saving all our silver from the lab, just throwing that out there.
Everyone better watch the Bears own the Dolphins tonight. And the next scribe is... Faith S.
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